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Consider the following standard electrode potentials and calculate `logK_(eq)` at `25^(@)C` for the indicated disproportion reaction. [Take `(2.303RT)/F=0.06V`] `3MN^(2+)(aq)arrMn(s)+2Mn^(3+)(aq)` `Mn^(3+)(aq)+e^(-)rarrMn^(2+)(a),E^(@)=1.51V` `Mn^(2+)(aq)+2e^(-)rarrMn(s),E^(@)=-1.185V`A. `-21.15`B. `-48.24`C. `-89.83`D. none of these |
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Answer» Correct Answer - C `2Mn^(2+)rarr2Mn^(3+)+2e^(-),DeltaG_(1)^(0)` `Mn^(2+)+2e(-)rarrMn, DeltaG_(2)^(0)` `3Mn^(2+)(aq)rarrMn(s)+2Mn^(3+)(aq)` `=2xxFxxE_(3)^(0)=-2xxF[-1.51]-2xxFxx(-1.185)` `E_(3)^(0)=-2.695V` `E_(3)^(0)=+(0.06)/2logK_(eq)` |
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