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Consider the following relations for emf of an electrochemical cell:(i) EMF of cell = (Oxidation potential of anode) – (Reduction potential of cathode)(ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode)(iii)) EMF of cell = (Reductional potential of anode) + (Reduction potential of cathode)(iv) ) EMF of cell = (Oxidation potential of anode) – (Oxidation potential of cathode) |
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Answer» Consider the following relations for emf of an electrochemical cell: |
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