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Consider the following reaction :2CH3 – CH2 – CH2 – OH + 2Na → 2CH3 – CH2– CH2 – ONa + H2Compare the structure of the substrate propanol with that of the product sodium propoxide. Which part of the substrate, the carbon skeleton or the OH group has undergone a change during the reaction? |
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Answer» In above reaction, The -OH group of the substrate molecule has undergone a change. The H-atom of hydroxyl group (-OH) is replaced by sodium forming the product. |
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