1.

Consider the following four electrodes P = Cu2+(.0001 M/Cu(s) Q = Cu2+ (0.1 M)/Cu(s) R = Cu2+(0.01 M)/Cu(s) S = Cu2+(0.001 M)Cu(s) If the standard reduction potential of Cu2+ /Cu is +.34V the reduction potential in volts of the above electrode follows the order.

Answer»

If the standard reduction potential of Cu2+/Cu is +.34V the reduction potential in volts of the above electrode follows the order. i.e.,

Q > R > P



Discussion

No Comment Found

Related InterviewSolutions