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Consider the following equation P = A sin (Bt + Ct2) + xHere t is time and x is length. The dimensions of AB/C will be ¤ [M°LT1]¤ [MºLT-2]¤ [MLT-1]¤ [MºL2T-2]​

Answer» P = A sin (Bt + Ct2) + x  , t is time and x is lengthTo Find  : The dimensions of AB/C Solution P = A sin (Bt + Ct²) + xsin (Bt + Ct²) is unit lessHence unit of A sin (Bt + Ct²)  is same as of A its added with xHence unit of A is same as of  xx is length Hence Dimension  of A = LBt   and  Ct²  are of same unit Dividing both by t Hence B  & Ct  are of same unitDividing both by C => B / C   has unit of  t  time=>  Dimension  of of B / C = T The dimensions of AB/C will be     LT= M⁰L¹T¹Learn MorE:In a new system of units, unit of MASS is taken as100 KG, unit of ... brainly.in/question/18852647The physical quantity having the same unit in all the systems of unit ... brainly.in/question/4617397


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