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Consider the following equation P = A sin (Bt + Ct2) + xHere t is time and x is length. The dimensions of AB/C will be ¤ [M°LT1]¤ [MºLT-2]¤ [MLT-1]¤ [MºL2T-2] |
| Answer» P = A sin (Bt + Ct2) + x , t is time and x is lengthTo Find : The dimensions of AB/C Solution P = A sin (Bt + Ct²) + xsin (Bt + Ct²) is unit lessHence unit of A sin (Bt + Ct²) is same as of A its added with xHence unit of A is same as of xx is length Hence Dimension of A = LBt and Ct² are of same unit Dividing both by t Hence B & Ct are of same unitDividing both by C => B / C has unit of t time=> Dimension of of B / C = T The dimensions of AB/C will be LT= M⁰L¹T¹Learn MorE:In a new system of units, unit of MASS is taken as100 KG, unit of ... brainly.in/question/18852647The physical quantity having the same unit in all the systems of unit ... brainly.in/question/4617397 | |