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Consider the family of circles `x^2+y^2-2x-2lambda-8=0`passing through two fixed points `Aa n dB`. Then the distance between the points `Aa n dB`is_____ |
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Answer» Correct Answer - 6 `x^(2)+y^(2)-2x-2lambda y -8=0` or `(x^(2)+y^(2)-2x-8)-2 lambda y =0` which is of the form of `S + lambda L =0` All the circles pass through the point of intersection of the circle `x^(2)+y^(2)-2x-8=0` and `y=0` Solving, we gt `x^(2)-2x+8=0` or `(x-4)(x+2) =0` `:. A -= (4,0)` and `B -= (-2,0)` So, the distance between A and B is 6. |
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