1.

Consider the family of circles `x^(2)+y^(2)-2x-2ay-8=0` passing through two fixed points A and B . Also, `S=0` is a cricle of this family, the tangent to which at A and B intersect on the line `x+2y+5=0`. The distance between the points A and B , isA. 4B. `4 sqrt(2)`C. 6D. 8

Answer» Correct Answer - 3
We have `x^(2)+y^(2) -2x-2ay-8=0`
or `(x^(2)+y^(2)-2x-8)-2ay =0`, which is of the form `S + lambda L =0`.
Solving `S -= x^(2)+y^(2) -2x-8=0` and `L -= y =0`, we get
`x^(2)-2x-8=0`
`implies (x-4) (x+2)=0`
`implies x = - 2` or `4`
`implies A -= (4,0) , B -= (-2,0)`
Distance between A and `B =6`


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