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Consider the expansion of `(2x-1)^(15)`A. Algebraically least coefficient is `T_(5)`B. Algebraically greatest coefficient is `T_(5)`C. Numerically greatest coefficient is `T_(6)`D. Numerically least coefficient is `T_(16)` |
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Answer» Correct Answer - B::C::D `rle(n+1)/(1+|(x)/(y)|)` `rle(16)/(1+|(2x)/(-1)|)` `rle(16)/(3)=5` `impliesT_(6)` gives numerically greatest coefficient `T_(6)= .^(15)C_(5)(-1)^(5)(2)^(10)(x)^(10)` `N.G.C= .^(15)C_(5)(2)^(10)` `N.I.C=1` `A.L.C= .^(15)C_(4)(2)^(10)` `A.G.C= .^(15)C_(4)(2)^(11)` |
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