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Consider the differential equation, y2 dx+(x−1y)dy=0. If value of y is 1 when x=1, then the value of x for which y=2, is: |
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Answer» Consider the differential equation, y2 dx+(x−1y)dy=0. If value of y is 1 when x=1, then the value of x for which y=2, is: |
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