1.

Consider the circuit shown in the figure. Find the charge on capacitor `C` between `A` and `D` in steady state. A. `C epsilon`B. `C epsilon // 2`C. `C epsilon // 3`D. zero

Answer» Correct Answer - D
(d) In steady state, there will be no current in any branch. So `A` and `D` will be at same potential. Hence charge on capacitor betwork `A` to `D` will be zero


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