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Consider the circuit provided.Total discharge time = 0.5 ms. Consider the diode to be an ideal diode, for a square wave input of ± 10 V, what is the percentage tilt? (C = 1MF & R = 50k Ohms)(a) 10%(b) 1%(c) 0.1%(d) 1.1%I have been asked this question in examination.Asked question is from Clamper Circuit in portion Diode Circuit of Analog Circuits |
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Answer» RIGHT answer is (B) 1% The EXPLANATION is: Total discharge time Td=0.5ms. For ideal diode, no cut-in VOLTAGE. % TILT = ΔVo/2Vm * 100 Idischarge = 2Vm/R = 2*10/50k = 0.4 mA ΔVo = Tdischarge*Idischarge/C = 0.5ms*0.4mA/1MF = 0.2 % Tilt = (0.2/20) * 100 = 1 %. |
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