Consider solving the system (1) 2y – 6 = 0, and (2) x + 3y = 5 using

1.	Consider solving the system (1) 2y – 6 = 0, and (2) x + 3y = 5 using the substitution method.11. What is the value of x? * a. 4b. -4c. 5d. -512. What is the value of y? *a. 3b. -3c. 4d. -4
Answer» ANSWER: 11-b) 12-a) Step-by-step explanation: 12.a)2y-6=0 2y=0+6 y=6/2=3 11.b)x+3y-5 x+9=5 x=5-9=-4 mark this BRAINLIEST PLEASE HOPE you UNDERSTOOD the answer.

Consider solving the system (1) 2y – 6 = 0, and (2) x + 3y = 5 using the substitution method.11. What is the value of x? * a. 4b. -4c. 5d. -512. What is the value of y? *a. 3b. -3c. 4d. -4

Answer»

ANSWER:

11-b)

12-a)

Step-by-step explanation:

12.a)2y-6=0

2y=0+6

y=6/2=3

11.b)x+3y-5

x+9=5

x=5-9=-4

mark this BRAINLIEST PLEASE HOPE you UNDERSTOOD the answer.

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Consider solving the system (1) 2y – 6 = 0, and (2) x + 3y = 5 using the substitution method.11. What is the value of x? * a. 4b. -4c. 5d. -512. What is the value of y? *a. 3b. -3c. 4d. -4​

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Consider solving the system (1) 2y – 6 = 0, and (2) x + 3y = 5 using the substitution method.11. What is the value of x? * a. 4b. -4c. 5d. -512. What is the value of y? *a. 3b. -3c. 4d. -4