Consider following equilibriums and their equilibrium constants of lys – InterviewSolution

1.	Consider following equilibriums and their equilibrium constants of lysine. H3N+−(CH2)4CH(NH+3)COOH pK=2.2⇌ H3N+−(CH2)4CH(NH+3)COO−+H+ H3N+−(CH2)4CH(NH2)COO−+H2O pK=5⇌ H3N+−(CH2)4CH(NH+3)COO−+OH− H2N−(CH2)4CH(NH2)COO−+H2O pK=3.4⇌ H3N+−(CH2)4CH(NH2)COO−+OH−
Answer» Consider following equilibriums and their equilibrium constants of lysine. $H_{3} N^{+} - (C H_{2})_{4} C H (N H_{3}^{+}) C O O H p K = 2.2 ⇌ H_{3} N^{+} - (C H_{2})_{4} C H (N H_{3}^{+}) C O O^{-} + H^{+}$ $H_{3} N^{+} - (C H_{2})_{4} C H (N H_{2}) C O O^{-} + H_{2} O p K = 5 ⇌ H_{3} N^{+} - (C H_{2})_{4} C H (N H_{3}^{+}) C O O^{-} + O H^{-}$ $H_{2} N - (C H_{2})_{4} C H (N H_{2}) C O O^{-} + H_{2} O p K = 3.4 ⇌ H_{3} N^{+} - (C H_{2})_{4} C H (N H_{2}) C O O^{-} + O H^{-}$

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