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Consider a wire of length 4m and cross - sectional area 1mm^(2) carrying a current of 2A. If each cubic metre of the material contains 10^(29) free electrons, find the average time taken by an electron to cross the length of the wire. |
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Answer» SOLUTION :`RARR v_(d)=(i)/(nAe)=(2)/(10^(29)xx10^(-6)xx1.6xx10^(-19))ms^(-1)` `=12.5xx10^(-4)ms^(-1)` `rArr"Average TIME takne by an electron to cross the LENGTHOF wire"` `t=(1)/(v_(d))=(4)/(1.25xx10^(-4))s=3.2xx10^(4)s` |
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