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Consider a straight line `x/a + y/b =1` , such that it cuts the asymptotes of hyperbola `xy = 1` in points A and B and the hyperbola itself in P and Q, then`(AP )/ (BQ) =lamda` lambda where `2lambda + 1` is |
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Answer» Correct Answer - 3 `A(a,0), B(0,b)` Put `y=1/x` `x^(2)-ax+a/b=0` and `x=1/y` `y^(2)-by+b/a=0` `AP^(2)=(x_(1)-a)^(2)+y_(1)^(2)=(a-x_(2)-a)^(2)+(b-h_(2))^(2)=x_(2)^(2)+(b-y_(2)^(2))=BQ^(2)` |
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