Consider a spherical drop of liquid having radius ‘R’. Assume a diametric cross-section which divides the drop into two hemispheres. The hemispheres pull each other due to surface tension along the circumference of the diametrical cross-section. What is the value of this force?(a) 2πRS(b) πR^2 S(c) 2RS(d) 0I had been asked this question during an interview.This intriguing question comes from Fluids Mechanical Properties in portion Mechanical Properties of Fluids of Physics – Class 11

Consider a spherical drop of liquid having radius ‘R’. Assume a di

1.	Consider a spherical drop of liquid having radius ‘R’. Assume a diametric cross-section which divides the drop into two hemispheres. The hemispheres pull each other due to surface tension along the circumference of the diametrical cross-section. What is the value of this force?(a) 2πRS(b) πR^2 S(c) 2RS(d) 0I had been asked this question during an interview.This intriguing question comes from Fluids Mechanical Properties in portion Mechanical Properties of Fluids of Physics – Class 11
Answer» Right choice is (a) 2πRS Best explanation: The diametrical cross section of a sphere will be a circle of radius R.One hemisphere will exert a force of SDL (DL is a SMALL ELEMENT of length along periphery) on dl length. Total length = perimeter of circle = 2&7pi;R. Therefore, total force = 2πRS.

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