1.

Consider a simple pendulum of length l = 0.9 m which is properly placed on a trolley rolling down on a inclined plane which is at 0 = 45°with the horizontal. Assuming that the inclined plane is frictionless. Assuming that the time period of oscillation of the simple pendulum is T.Find the value of T.

Answer»

Solution :LENGTH of the pendulum `l=0.9m`
Inclined ANGLE `theta=45^(@)`
TIME period of a SIMPLE pendulum `T=2pisqrt((l)/(G.))`
`g.=gcostheta`
`T=2pisqrt((l)/(gcostheta))=2xx3.14sqrt((0.9)/(9.8xxcos45^(@)))=6.28xxsqrt(0.1298)`
`T=2.263s`


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