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Consider a simple pendulum of length l = 0.9 m which is properly placed on a trolley rolling down on a inclined plane which is at 0 = 45°with the horizontal. Assuming that the inclined plane is frictionless. Assuming that the time period of oscillation of the simple pendulum is T.Find the value of T. |
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Answer» Solution :LENGTH of the pendulum `l=0.9m` Inclined ANGLE `theta=45^(@)` TIME period of a SIMPLE pendulum `T=2pisqrt((l)/(G.))` `g.=gcostheta` `T=2pisqrt((l)/(gcostheta))=2xx3.14sqrt((0.9)/(9.8xxcos45^(@)))=6.28xxsqrt(0.1298)` `T=2.263s` |
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