Consider a rectangle ABCD having 5,7,6,9 points in the interior of the line segments AB, CD, BC, DA respectively. Let α be the number of triangles having these points from different sides as vertices and β be the number of quadrilaterals having these points from different sides as vertices. Then (β−α) is equal to :

Consider a rectangle ABCD having 5,7,6,9 points in the interior of the

1.	Consider a rectangle ABCD having 5,7,6,9 points in the interior of the line segments AB, CD, BC, DA respectively. Let α be the number of triangles having these points from different sides as vertices and β be the number of quadrilaterals having these points from different sides as vertices. Then (β−α) is equal to :
Answer» Consider a rectangle $A B C D$ having $5, 7, 6, 9$ points in the interior of the line segments $A B,$ $C D,$ $B C,$ $D A$ respectively. Let $α$ be the number of triangles having these points from different sides as vertices and $β$ be the number of quadrilaterals having these points from different sides as vertices. Then $(β - α)$ is equal to :

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