1.

consider a proper fraction such that the numerator is 2 less than the denominator. if the numerator and denominator are each increased by 1, then the ratio of the numerator and denominator of the new fraction is 4:5. determine the original fraction

Answer»

Answer:-

LET the fraction be x/y.

Given:

Numerator is 2 less than the denominator.

⟶ Numerator = denominator - 2

x = y - 2 -- equation (1)

And,

If numerator and denominator are increased by 1 , the RATIO of numerator and denominator is 4 : 5.

According to the above condition,

\longrightarrow \sf \:  \dfrac{x + 1}{y + 1}  =  \dfrac{4}{5}

Substitute the VALUE of x from equation (1).

\longrightarrow \sf \:  \frac{y - 2 + 1}{y + 1}  =  \frac{4}{5}  \\  \\ \longrightarrow \sf \:5(y - 1) = 4(y + 1) \\  \\ \longrightarrow \sf \:5y - 5 = 4y + 4 \\  \\ \longrightarrow \sf \:5y - 4y = 4 + 5 \\  \\ \longrightarrow \boxed{ \sf \:y = 9}

Substitute the value of y in equation (1)

⟶ x = y - 2

⟶ x = 9 - 2

⟶ x = 7

The original fraction x/y is 7/9



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