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Consider a one-dimensional motion of a particle with total energy E. There are four regions A, B, C and D is which the relation between potential energy U, kinetic energy (K) and total energy E is as given below RegionA:`UgtE` Region B:`UltE` Region C:`KltE` Region D:`UgtE` State with reason in each case whether a particle can be found in the given region or not. |
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Answer» We know that Total ME=KE+PE `Rightarrow E_(0)=KE+V(x)` ltbRgt `Rightarrow KE=E_(0)-V(x)` at `A_(1) x=0,V(x)=E_(0)` `Rightarrow KE=E_(0)-E_(0)=0` at `B_(1) V(x) gt E_(0)` `Rightarrow KE gt0` at C and `D_(1) V(x)=0` This is possible because total energy can be greater than PE(V). For region C Given, `K gt E Rightarrow K -E gt 0` From Eq. (i) PE=V=E-Klt0 Which is possible, because PE can be negative For region D Given,` V gt K` This is possible because for a system PE(V) may be greater than KE(K) |
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