1.

Consider a heat engine as shown in figure. Q_1 and Q_2 are heat added both to T_1 and heat taken from T_2 in one cycle of engine. W is the mechanical work done on the engine. If W gt 0, then possibilities are :

Answer»

`Q_1 gt Q_2 gt 0`
`Q_2 gt Q_1 gt 0`
`Q_2 lt Q_1 lt 0`
`Q_1 lt 0,Q_2 gt 0`

Solution :From FIGURE ,
`Q_1=W+Q_2`
`THEREFORE W=Q_1-Q_2`
But W `gt` 0
`therefore Q_1-Q_2 gt 0`
`therefore Q_1 gt Q_2` if `Q_1` and `Q_2` both are positive but if `Q_1` and `Q_2` both are negative then
`Q_2 -Q_1 lt 0`
`therefore Q_2 lt Q_1`
HENCE, `Q_2 lt Q_1 lt 0`


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