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Consider a gas contained in a rigid container of volume 20m^3. What will be the change in internal energy if 50J of heat is provided to it? Assume the gas exerts a pressure of 1atm on the walls.(a) 50J(b) 0(c) 70J(d) 20JI had been asked this question during an interview.My question is based upon First Law of Thermodynamics topic in chapter Thermodynamics of Physics – Class 11

Answer»

Correct CHOICE is (a) 50J

Easy explanation: All the heat supplied will be equal to change in internal energy.

The WORK DONE is zero because the container is rigid hence no VOLUME change.

Thus, ΔU = ΔQ – ΔW = 50 + 0 = 50J.



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