Consider a function f:R→R is periodic function with period π and is defined in [0,π] as f(x)=⎧⎪⎪⎨⎪⎪⎩1−cosx, 0≤x<π22−2xπ, π2≤x≤π Then the area(in sq.units) bounded by y=f(x) and the x−axis from x=−nπ to x=nπ(n∈Z+), is

Consider a function f:R→R is periodic function with period π and is

1.	Consider a function f:R→R is periodic function with period π and is defined in [0,π] as f(x)=⎧⎪⎪⎨⎪⎪⎩1−cosx, 0≤x<π22−2xπ, π2≤x≤π Then the area(in sq.units) bounded by y=f(x) and the x−axis from x=−nπ to x=nπ(n∈Z+), is
Answer» Consider a function $f : R \to R$ is periodic function with period $π$ and is defined in $[0, π]$ as $f (x) = ⎧ ⎪⎪ ⎨ ⎪⎪ ⎩ \begin{matrix} 1 - cos x, 0 \leq x < \frac{π}{2} 2 - \frac{2 x}{π}, \frac{π}{2} \leq x \leq π \end{matrix}$ Then the area(in $sq.units$ ) bounded by $y = f (x)$ and the $x -$ axis from $x = - n π$ to $x = n π (n \in Z^{+}),$ is