Consider a concave mirror and a convex lens (refractive index =1.5) of focal length 10 cm each, separated by a distance of 50 cm in air (refractive index =1) as shown in the figure. An object is placed at a distance of 15 cm from the mirror. Its erect image formed by this combination has magnification M1. When the set-up is kept in a medium of refractive index 76, the magnification becomes M2. The magnitude ∣∣∣M2M1∣∣∣ is

Consider a concave mirror and a convex lens (refractive index =1.5) of

1.	Consider a concave mirror and a convex lens (refractive index =1.5) of focal length 10 cm each, separated by a distance of 50 cm in air (refractive index =1) as shown in the figure. An object is placed at a distance of 15 cm from the mirror. Its erect image formed by this combination has magnification M1. When the set-up is kept in a medium of refractive index 76, the magnification becomes M2. The magnitude ∣∣∣M2M1∣∣∣ is
Answer» Consider a concave mirror and a convex lens (refractive index $= 1.5$ ) of focal length $10 cm$ each, separated by a distance of $50 cm$ in air (refractive index $= 1$ ) as shown in the figure. An object is placed at a distance of $15 cm$ from the mirror. Its erect image formed by this combination has magnification $M_{1}$ . When the set-up is kept in a medium of refractive index $\frac{7}{6}$ , the magnification becomes $M_{2}$ . The magnitude $∣ ∣ ∣ \frac{M_{2}}{M_{1}} ∣ ∣ ∣$ is