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Consider a carnot's cycle operating between T_(1)=500 K and T_(2)=300K producing 1 kJ of mechanical work per cycle. Find the heat transferred to the engine by the reservoirs. |
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Answer» Solution :`Q_(2)/Q_(1)=T_(2)/T_(1)=3/5, Q_(1)-Q_(2)=W=10^(3)J` `:. Q_(1)[1-Q_(2)/Q_(1)]=10^(3)J` `:. Q_(1)[1-3/5]=10^(3)J` `:. Q_(1)=5/2xx10^(3)=2500J`2 and `Q_(2)=Q_(1)3/5=1500J` |
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