1.

consecutiveoddintegers such that the sum of the first is two less than the second, and three7.more than the third is 70

Answer»

If the first number is n the second number is 2 more than n and the third number is 4 more than n. And, here is how you mathematically represent that

n + 2(n + 2) + 3(n + 4) = 70

n + 2n + 4 +3n + 12 = 70

6n + 16 = 70

6n = 54

n = 9

=> The numbers are 9, 11, 13



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