Conductivityof 0.00241 M acetic acid is 7.896 × 10−5S cm−1.Calcul – InterviewSolution

1.	Conductivityof 0.00241 M acetic acid is 7.896 × 10−5S cm−1.Calculate its molar conductivity and if foracetic acid is 390.5 S cm2mol−1,what is its dissociation constant?
Answer» Conductivity of 0.00241 M acetic acid is 7.896 × 10⁻⁵ S cm⁻¹. Calculate its molar conductivity and if for acetic acid is 390.5 S cm² mol⁻¹, what is its dissociation constant?

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