Conductivity of 0.00241M acetic is 7.896×10−5S cm−1 Calculate its – InterviewSolution

1.

Conductivity of 0.00241M acetic is 7.896×10−5S cm−1 Calculate its molar conductivity. If λ∘m for acetic acid is 390.5 S cm2mol−1, what is its dissociation constant ?

Answer»

Conductivity of 0.00241M acetic is $7.896 \times 10^{- 5} S c m^{- 1}$

Calculate its molar conductivity. If $λ_{m}^{\circ}$ for acetic acid is $390.5 S c m^{2} m o l^{- 1}$ , what is its dissociation constant ?

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