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Concentrated `HNO_(3)` is 69% by mass of nitric acid. Calculate the volume of the solution which contains `23 g` of `HNO_(3)`. (Density of concentrated `HNO_(3)` solution is `1.41 g ml^(-1))` |
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Answer» `69 g NHO_(3) = 100 g` of solution `23 g of HNO_(3) = (100)/(69) xx 33.3 g` Volume of solution `= (33.3)/(1.41) = 23.6 mL` |
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