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Compute the position of an oscillating particle when its kinetic energy and potential energy are equal. |
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Answer» Solution :SINCE the kinetic energy and POTENTIAL energy of the oscillating particle are equal, `(1)/(2)momega^(2)(A^(2)-X^(2))=(1)/(2)momega^(2)x^(2)` `implies A^(2)-x^(2)=x^(2)` `implies 2x^(2)=A^(2)impliesxpm(A)/(sqrt(2))` |
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