Composite Matheathematics - VIeter and AreaMr. Veto fence it widGiven : LengthBarbed wirema has an orchard of length and bye it with 4 rounds of barbed wire. E· Length of the orchard = 280 m, Breadarbed wire required for 1 round of fencing = Perh 280 m and 200 m respectively.d the cost of fencing at 35 per mereadth of the orchard = 200 m.ing = Perimeter of the orchard= 2 (length + breadth) = 2 (280 m+= 2 x 480 m = 960 m[ 4 rounds of fencing = 4 x 960 m = 3840 mI ength of barbed wire required for 4 rounds of teCost of fencing at 35 per metre =3 (3840 x 35)Metre =* (3840 x 35) =1,34,400.EXERCISE 15 (A)ind the breadth of the rectangle whoseCerimeter is 160 cm and whose length is:cm = 460 cm.)25 cm(a) 25 cm(b) 60 cm(0) 56.5 cm? | Perimeter = 160 cm?perimeter 200 cm.dth), we have25 cmFind the length of the rectangle if the perimeterand width are:(a) Perimeter = 86 cm, width = 18 cm(b) Perimeter = 128 cm, width= 25 cmfor Perimeter = 151 cm, width = 29.5 cmArectangular field is 72 m by 5€round it at the rate of 3 km perwill he take in taking 2 rounds7. A rectangular garden is 120many rounds of this gardenbe covers 2200 metres ?8. A lid of rectangular box of sis sealed all around with taan overlapping of 5 cm oflength of the tape used ?Multiple Choice Questi9 Find the length of a w7 = 30 cm.1. obmouired to frame a pair​