1.

Complete the following calculations. Show working for complete credit:Calculate the mass of Calcium that will contain the same number of atoms as are present in 3.2 gm of Sulphur. [Atomic masses: S = 32, Ca = 40]

Answer»

32 gm of Sulpher = 1 mole

3.2 gm of Sulphur = \(\frac{1}{32}\times3.2 \)

= 0.1 moles

At. Mass of Calcium = 40

∴ mass of 0.1 mole of Ca = 40 x 0.1 = 4 gm



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