Saved Bookmarks
| 1. |
Complete the following calculations. Show working for complete credit:Calculate the mass of Calcium that will contain the same number of atoms as are present in 3.2 gm of Sulphur. [Atomic masses: S = 32, Ca = 40] |
|
Answer» 32 gm of Sulpher = 1 mole 3.2 gm of Sulphur = \(\frac{1}{32}\times3.2 \) = 0.1 moles At. Mass of Calcium = 40 ∴ mass of 0.1 mole of Ca = 40 x 0.1 = 4 gm |
|