1.

Complement of the expression A'B+CD' is

Answer»

By DE morgans law you should know that,


A' + B' = (AB)' ................1)


Also,


A'B' = (A + B)' .................2)


So,

(A'B + CD')'


=(A'B)' . (C.D')' ..........................From 2)


=(A+ B').(C' + D).........................From 1)


=(A+ B').(C' + D)


For more practical output it can be further splited into,


AC' + AD + B'C' + B'D


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