Combustion Reaction Of Methane:- CH4(s)+2O2(g)=CO2(g)+H2O(l), H=(-890. – InterviewSolution

1.	Combustion Reaction Of Methane:- CH4(s)+2O2(g)=CO2(g)+H2O(l), H=(-890.30)KJ,If We Have To Get 445.15KJ Combustion Energy How Many Gram Methane Have To Combust? A. 4 gm B. 8 gm C. 12 gm D. 16 gm
Answer» Combustion Reaction Of Methane:- CH4(s)+2O2(g)=CO2(g)+H2O(l), H=(-890.30)KJ,If We Have To Get 445.15KJ Combustion Energy How Many Gram Methane Have To Combust? A. 4 gm B. 8 gm C. 12 gm D. 16 gm

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