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Combustion of sucrose is used by aerobic organisms for providing energy for the life sustaining process. If all the capturing of energy from the reaction is done through electrical process (non P-V work), then calculate, maximum available energy which can be captured by combustion of 34.2 g of sucrose : (Given : `DeltaH_("combustion")("sucrose")=-6000kJmol^(-1)` `DeltaS_("combustion")=180j//K-mol` and bodyntemperature is 300 K)A. 60 kJB. 59.46 kJC. 0.54 kJD. 60.54kJ |
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Answer» (D) Maximum non P-V work `=|DeltaG_(R)|` `implies DeltaG=DeltaH=TDeltaS` `implies DeltaG=-6000-(300xx180)/(1000)`(for 1 mole ) `implies DeltaG=-6054kJ` `implies |DeltaG|` for 0.01 mole of sucrose `implies 60.54 kJ` option (D) |
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