COF2(g) passed over catalyst at 1000 ∘C comes to equilibrium: 2COF2( – InterviewSolution

1.	COF2(g) passed over catalyst at 1000 ∘C comes to equilibrium: 2COF2(g)⇌CO2(g)+CF4(g) Analysis of the equilibrium mixture (after quick cooling to freeze the equilibrium) show that 500 ml of the equilibrium mixture (STP) contain 300 ml (STP) of (COF2+CO2) taking the total pressure to be 10 atm. The value of Kp for the reaction is :
Answer» $C O F_{2} (g)$ passed over catalyst at $1000^{\circ} C$ comes to equilibrium: $2 C O F_{2} (g) ⇌ C O_{2} (g) + C F_{4} (g)$ Analysis of the equilibrium mixture (after quick cooling to freeze the equilibrium) show that $500 ml$ of the equilibrium mixture (STP) contain $300 ml$ (STP) of $(C O F_{2} + C O_{2})$ taking the total pressure to be $10$ atm. The value of $K_{p}$ for the reaction is :

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