[co(en) Cl2] Cl how to calculate oxidation state of cobalt ?what is it

1.	[co(en) Cl2] Cl how to calculate oxidation state of cobalt ?what is its IUPAC name?
Answer» ong>Explanation: Co(NH3 )4(H2O)Cl]SO4 In the above compound, Oxidation state of AMMONIA, (NH 3 )=0 Oxidation state of water, (H2O)=0 Oidation state of chlorine, (Cl)=−1 Oxidation state of sulphate ion, (SO4 )=−2 Let the oxidation state of cobalt, (Co) be x. As we know that SUM of oxidation STATES of all atoms is equal to the overall CHARGE on the compound. ∴x+(4×0)+(1×0)+(−1)+(−2)=0 ⇒x+0+0−1−2=0 ⇒x−3=0 ⇒x=+3 Hence, the oxidation state of cobalt, (Co) in the compound [Co(NH3)4(H2O)Cl]SO4is +3.

[co(en) Cl2] Cl how to calculate oxidation state of cobalt ?what is its IUPAC name?

Answer»

ong>Explanation:

Co(NH3 )4(H2O)Cl]SO4

In the above compound,

Oxidation state of AMMONIA, (NH

3 )=0

Oxidation state of water, (H2O)=0

Oidation state of chlorine, (Cl)=−1

Oxidation state of sulphate ion, (SO4 )=−2

Let the oxidation state of cobalt, (Co) be x.

As we know that SUM of oxidation STATES of all atoms is equal to the overall CHARGE on the compound.

∴x+(4×0)+(1×0)+(−1)+(−2)=0

⇒x+0+0−1−2=0

⇒x−3=0

⇒x=+3

Hence, the oxidation state of cobalt, (Co) in the compound [Co(NH3)4(H2O)Cl]SO4is +3.