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CミARPQ, LA = 60° and LB-50°. Find LP, LQ and LR.150) |
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Answer» ∆ABC~=∆RPQ-------------. givenSo,angle A=angleRAngleR=60°---------given angleA=60angleB=anglePangleP=50°-----------given angleB=50° Sum of all angles in a triangle is 180°Therefore,angleR+angleP+angleQ=18060+50+angleQ=180angleQ=180-110angleQ=70° |
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