Classify each of the following complexes as either high or low spin. Explain your answers[Co(H_(2)O)_(6)]^(2+),mu=4.6B.M.and[Co(CN)_(6)]^(4-),mu=1.9 B.M.Fe(NO_(2))_(6)]^(4-),mu=0.0 B.M.and[Fe(H_(2)O)_(6)]^(3+),mu=5.94 B.M.

Classify each of the following complexes as either high or low spin. E

1.	Classify each of the following complexes as either high or low spin. Explain your answers[Co(H_(2)O)_(6)]^(2+),mu=4.6B.M.and[Co(CN)_(6)]^(4-),mu=1.9 B.M.Fe(NO_(2))_(6)]^(4-),mu=0.0 B.M.and[Fe(H_(2)O)_(6)]^(3+),mu=5.94 B.M.
Answer» Solution :ntains `Co^(2+)` ion in an octahedral field. Obviously, the compound `[Co(H_(2)0)_(6)]^(2+)` is high spin having a MAGNETIC moment value of 4.6 B.M. whereas `(Co(CN)_(6)]^(4-)` is low spin with a magnetic moment value of 1.9 B.M. (ii) The complex `[Fe(NO_(2))_(6)]^(4-)` CONTAINS `Fe^(2+)` which belongs to a `d_(6)` system. As the magnetic moment of the complex is zero, it indicates that all the six d-electrons are paired up. Hence the compound is low spin. On the other hand, the magnetic moment of 5.94 B.M. for the complex `Fe(H_(2)O)_(6)]^(3+)` CORRESPONDS to FIVE unpaired electrons in Fe. It indicates there is no pairing of d-electrons of `Fe^(3+)` ion, hence the complex is high spin.