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Class 7 maths. Pls tell fast but correct. ​

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\large\fbox\red{Answer}

\dag\:\underline{\sf GiveN \::}

  • \sf↦\:(\frac{2}{a})^{3} \times (\frac{2}{a}) ^{6}=(\frac{2}{a}) ^{2x-1}

\dag\:\underline{\sf SolutioN \::}

\sf↦\:(\frac{2}{a})^{3} \times (\frac{2}{a}) ^{6}=(\frac{2}{a}) ^{2x-1}

We KNOW,

\tt\purple{a^{m} \times a^{n} = a^{m+n}}

\sf↦\:(\frac{2}{a})^{3+6}=(\frac{2}{a}) ^{2x-1}

\sf↦\:(\frac{2}{a})^{9}=(\frac{2}{a}) ^{2x-1}

\sf↦\:9=2x-1

\sf\:oR \:2x-1=9

\sf ↦\:2x=9+1

\sf↦\:2x=9+1

\sf↦\:2x=10

\sf↦\:x=\frac{10}{2}

\tt\pink{↦\:x=5}



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