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Class 10th mathematics, question!please provide me some reason if you know the answer!​

Answer»

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\longrightarrow 1) \Large\frac{PZ}{XZ}

Step-by-step explanation:

\Large\underline\mathtt{\red{Question:-}}

\implies Find:- \frac{ZX}{ZY} from the figure in the attachment.

\Large\underline\mathtt{\blue{Hint:-}}

\Large\underline\mathtt{\purple{Solution:-}}

In ∆ YXZ and ∆ PXZ;

\angle YZX = \angle PZX (common)

\angle YXZ = \angle XPZ (given)

\therefore ∆ YXZ ~ ∆ PXZ (by AA)

\implies \frac{PZ}{XZ} = \frac{ZX}{ZY} = \frac{YZ}{XZ}

(As corresponding sides of similar TRIANGLES are in proportion)

Hence, option 1 is correct.

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\tiny\mathfrak{\red{@MissTranquil}}



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