Class 10Mathematics Chapter 8 - Introduction to TrigonometryFormulas N

1.	Class 10Mathematics Chapter 8 - Introduction to TrigonometryFormulas Needed Quality Answer Needed .
Answer» ANSWER: Step-by-step explanation: The formulas required for Trigonometry are :- $\sf{ sin \theta = \dfrac{Height}{Hypotenuse}}$ $\sf{ cos \theta = \dfrac{Base}{Hypotenuse}}$ $\sf{ tan \theta = \dfrac{Height}{Base}}$ $\sf{ cot \theta = \dfrac{Base}{Height}}$ $\sf{ sec \theta = \dfrac{Hypotenuse}{Base}}$ $\sf{ cosec \theta = \dfrac{Hypotenuse}{Height}}$ From this, we can DERIVE RELATIONS as:- $\sf{ sin \theta = \dfrac{1}{Cosec \theta}}$ $\sf{ cos \theta = \dfrac{1}{Sec \theta}}$ $\sf{ Tan \theta = \dfrac{1}{ Cot \theta}}$ $\sf{ cot \theta = \dfrac{1}{tan \theta}}$ $\sf{ sec \theta = \dfrac{1}{cos \theta}}$ $\sf{ cosec \theta = \dfrac{1}{Sin \theta}}$ SQUARING Identities :- $\sf{ sin^2 \theta = 1 - cos^2 \theta}$ $\sf{ tan^2 \theta = sec^2 \theta - 1}$ $\sf{ cot^2 \theta = cosec^2 \theta - 1}$ External formulas:- $\sf{ tan \theta = \dfrac{sin \theta}{cos \theta}}$ $\sf{ cot \theta = \dfrac{cos \theta}{sin \theta}}$