Claculate the amount of water (g) produced by the combustion of 16 g o

1.	Claculate the amount of water (g) produced by the combustion of 16 g of methane
Answer» Explanation: Combustion of METHANE : CH4+2O2⟶CO2+2H2O Given WEIGHT of methane =16G Molecular weight of methane =16g No. of moles of methane in 16g of it =mol. wt.given wt.=1616=1 mole From the reaction, AMOUNT of water produced by the combustion of 1 mole of methane = 2 moles weight of 1 mole of water =18g ⇒ weight of 2 moles of water =2×18=36g Since, the given weight of methane is 16 g, hence the water produced by the combustion of 16 g of methane is 36 g.

Claculate the amount of water (g) produced by the combustion of 16 g of methane

Answer»

Explanation:

Combustion of METHANE :

CH4+2O2⟶CO2+2H2O

Given WEIGHT of methane =16G

Molecular weight of methane =16g

No. of moles of methane in 16g of it =mol. wt.given wt.=1616=1 mole

From the reaction,

AMOUNT of water produced by the combustion of 1 mole of methane = 2 moles

weight of 1 mole of water =18g

⇒ weight of 2 moles of water =2×18=36g

Since, the given weight of methane is 16 g, hence the water produced by the combustion of 16 g of methane is 36 g.