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Answer»

Distance travelled by the train = 480 kmLet the speed of the train be x kmphTime taken for the journey = 480/xGiven speed is decreased by 8 kmphHence the new speed of train = (x – 8) kmphTime taken for the journey = 480/(x – 8)480/x-8 =480/x=3480 (x-x+8)/x(x-8)=3480/3×8 =x^2-8x

1280 = x2– 8xx2– 8x – 1280 = 0On solving we get x = 40Thus the speed of train is 40 kmph

The quadratic equation isx2-8x-1280=0



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