1.

Choose the correct reaction:

Answer»

`BaCl_(2)+AcOH+K_(2)CrO_(4)to`yellow ppt.
`BaCO_(3)(s)+K_(2)C_(2)O_(4)+AcOH to`white ppt.
`BaCO_(3)(s) +K_(2)CrO_(4)+AcOH to`No ppt.
`SrCO_(3)(s)+K_(2)CrO_(4)+AcOH to`No ppt.

Solution :`Ba^(2+)` IONS produce yellow ppt. with `CrO_(4)^(2-)`, which is not soluble in `CH_(3)COOH`
`BaCO_(3)` dissolves in `CH_(3)COOH` and produces `Ba^(2+)` ion which gives yellow ppt. with `CrO_(4)^(2-)` which is insoluble in `CH_(3)COOH`
`SrCO_(3)` is soluble in `CH_(3)COOH` and produces `Sr^(2+)` ion which does not GIVE yellow ppt. of `SrCrO_(4)` in `CH_(3)COOH`.


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