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Choose the correct rate law for the elementary reversible reaction 3A ⇌ B + 2C.(a) –rA = kCA^3 – CBCC^2/KC(b) –rA = k[CA^3 – CBCC^2KC](c) –rA = k[CA^3 – CBCC^2]/KC(d) –rA = k[CA^3 – CBCC^2/KC] |
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Answer» Correct choice is (d) –rA = k[CA^3 – CBCC^2/KC] Easiest explanation: Let’s say the rate constant for the forward reaction is k1 and for the backward reaction it is k2. Rate of disappearance of A = k1CA^3 Rate of formation of A = k2CBCC^2 -rA = k1CA^3 – k2CBCC^2. We know that KC = k1/k2. So, -rA = k[CA^3 – CBCC^2/KC]. |
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