1.

Choose the correct matching of transition metal with magnetic moment give: {:(,"Transition Metal","Magnetic moment(B.M)"),(,(A)"Titanium (III)",(1) 4:9),(,(B)"Vandium (II)",(2) 1.73),(,(C )"Iron (II),(3)3.87):}

Answer»

A-2,B-3,C-1
A-1,B-3,C-2
A-3,B-1,C-2
C-1,B-3,C-2

Solution :`mu=sqrt(N(n+2))`,(n=no. of unpaired electrons)
(a) `mu=sqrt(n(n+2))`, (n= no. of unpaired electrons )
`Ti^(3+) to [Ar]3d^(1),mu=sqrt(1(1+2))=sqrt(3)=1.73 BM`
`V^(2+) to [Ar]3d^(3),mu=sqrt(3(3+2))=sqrt(15)=3.87 BM`
`FE^(2+) to [Ar]3d^(4),mu=sqrt(4(4+2))=sqrt(24)=4.89 BM`


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