1.

Choose correct optio for working given cell : Pt|underset("1 bar")(Cl_(2(g)))||Cl_((c_(2)))^(-)|underset("1 bar")(Cl_(2(g)))|Pt

Answer»

`C_(2) gt C_(1)`
`C_(1) gt C_(2)`
`E_(CELL)^(@)=0`
`DeltaG=-ve`

Solution :`underset(C_(1))(CL^(-)) to underset(C_(2))(Cl^(-))`
`E_(cell)=-0.059log((C_(2))/(C_(1)))=0.059log((C_(1))/(C_(2)))`
So, `C_(1) gt C_(2)`, so for the SPONTANEOUS reaction `C_(2) gt C_(1)` is not proper.


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