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Chlorine is prepared in the laboratory by treating manganese dioxide (MnO2) with aqueous hydrochloric acid according to the reaction 4HCl (aq) + MnO2(s) → 2H2O(l) + MnCl2(aq) + Cl2(g) How many grams of HCl react with 5.0 g of manganese dioxide? |
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Answer» 1 mol of MnO2 = 55+32 g = 87 g 87 g of MnO2 react with 4 moles of HCl i.e. 4×36.5 g = 146 g of HCl. ∴ 5.0 g of MnO2 will react with HCl = 146/87×5.0 g = 8.40 g. |
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