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Chlorine is prepared in the laboratory by treating manganase dioxide (MnO2) with aqueous hydrochloric acid according to the reaction, 4HCl(aq) + MnO2 (s) → 2H2O(l) + MnCl2(aq) + Cl2 (g) How many grams of HCl react with 5.0 g of manganese dioxide?(Atomic mass of Mn = 54.94 u) |
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Answer» 1 mol of MnO2 , i.e., 54.94 + 32 = 86.94 g MnO2 react with 4 moles of HCl, i.e., 4 × 36.5 g = 146 g of HCl. ∴ Mass of HCl reacting with 5.0 g of MnO2 = \(\frac{146}{86.94}\times5g\) = 8.4g |
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